Aerocarnival

4)It took MegaTech, Inc. 100,000 labor-hours to produce the eldest of several oil bore rigs for frozen exploration. Your company, Natural Resources, Inc. has agreed to purchase the fifth oil boring rig from their manufacturing yard. Assume that MegaTech experiences a learning prescribe of 80%. At a labor rate of $35 per hour, what should you, as the purchasing agent expect to pay for the fifth building block? Remember, the simplified formula for calculating learning rate rhythm is given as: TN = T1C Where, TN = Time needed to produce the ordinal building block T1= Time needed to produce the first unit C= acquirement curved shape coefficient Answer The panel lists the fourth unit learning curve coefficient as .596, assuming a learning rate of 80%. Using the formula, to produce the fifth unit takes: T5 = (100,000) (.596) = 59,600 hours To find the personify, calculate the hours by the periodical rate: = (59,600) ($35 per hour) = $2,086,000 6)Suppose that you ar the assigning costs to a major final cause to be undertaken by your firm, DynoSoft Applications, this year. One special(a) code process involves some(prenominal) labor hours, but highly bare work. You anticipate a total of 200,000 labor hours to complete the first grummet of the coding and a learning curve rate of 70%.

You be attempting to estimate the cost of the twentieth loop of this coding sequence. establish on the above information and at a $60 per hour labor rate, what would you expect to budget as the cost of the twentieth loop-the-loop? The fortieth itera tion? Answer T20=T1C =(200,000) (.214) =! 42,800 hours T40=T1C =(200,000) (.150) =30,000 hours The costs for the twentieth and 40th iterations atomic make out 18 found as: 20th iteration: (42,800 hours) ($60 per hour) =$2,568,000 40th iteration: (30,000 hours) ($60 per hour) =$1,800,000 7)Assume you are a project cost engineer calculating the cost of a repetitious activity for your project. There are a total of 20...If you compulsion to get a full essay, straddle it on our website: BestEssayCheap.com

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